sin3x-sin7x=√3sin2x

2sin(3x-7x)/2 *cos(3x+7x)/2 = √3sin2x

-2sin2x *cos5x - √3sin2x = 0

sin2x(2cos5x +√3) = 0

sin2x=0     2x = Пk,    x= Пk/2, kCZ

cos5x= -√3/2      5x= ±(П-П/6) +2Пk,    5x= ±5П/6 +2Пk, 

x= ±П/6 + 2Пk/5,   kCZ